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15043345141 = 111367576831
BaseRepresentation
bin11100000001010011…
…10011101011110101
31102211101201010001011
432000221303223311
5221302044021031
610524423032221
71041534216046
oct160051635365
942741633034
1015043345141
11641a637950
122ab9b9b671
131559814376
14a29ca88cd
155d0a276b1
hex380a73af5

15043345141 has 4 divisors (see below), whose sum is σ = 16410921984. Its totient is φ = 13675768300.

The previous prime is 15043345103. The next prime is 15043345151. The reversal of 15043345141 is 14154334051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 15043345141 - 27 = 15043345013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15043345151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 683788405 + ... + 683788426.

It is an arithmetic number, because the mean of its divisors is an integer number (4102730496).

Almost surely, 215043345141 is an apocalyptic number.

15043345141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

15043345141 is a deficient number, since it is larger than the sum of its proper divisors (1367576843).

15043345141 is a wasteful number, since it uses less digits than its factorization.

15043345141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1367576842.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 15043345141 its reverse (14154334051), we get a palindrome (29197679192).

The spelling of 15043345141 in words is "fifteen billion, forty-three million, three hundred forty-five thousand, one hundred forty-one".

Divisors: 1 11 1367576831 15043345141