Base | Representation |
---|---|
bin | 11100000001010011… |
… | …10011101011110101 |
3 | 1102211101201010001011 |
4 | 32000221303223311 |
5 | 221302044021031 |
6 | 10524423032221 |
7 | 1041534216046 |
oct | 160051635365 |
9 | 42741633034 |
10 | 15043345141 |
11 | 641a637950 |
12 | 2ab9b9b671 |
13 | 1559814376 |
14 | a29ca88cd |
15 | 5d0a276b1 |
hex | 380a73af5 |
15043345141 has 4 divisors (see below), whose sum is σ = 16410921984. Its totient is φ = 13675768300.
The previous prime is 15043345103. The next prime is 15043345151. The reversal of 15043345141 is 14154334051.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 15043345141 - 27 = 15043345013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15043345151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 683788405 + ... + 683788426.
It is an arithmetic number, because the mean of its divisors is an integer number (4102730496).
Almost surely, 215043345141 is an apocalyptic number.
15043345141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
15043345141 is a deficient number, since it is larger than the sum of its proper divisors (1367576843).
15043345141 is a wasteful number, since it uses less digits than its factorization.
15043345141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1367576842.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 15043345141 its reverse (14154334051), we get a palindrome (29197679192).
The spelling of 15043345141 in words is "fifteen billion, forty-three million, three hundred forty-five thousand, one hundred forty-one".
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