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15048295931341 = 31485428901011
BaseRepresentation
bin1101101011111011010001…
…0101010101110111001101
31222021121021121122220010101
43122332310111111313031
53433022402224300331
652001031451011101
73112126541633131
oct332766425256715
958247247586111
1015048295931341
114881a45821622
121830563a39a91
13852081c1a04a
143a04acb813c1
151b1692600061
hexdafb4555dcd

15048295931341 has 4 divisors (see below), whose sum is σ = 15533724832384. Its totient is φ = 14562867030300.

The previous prime is 15048295931257. The next prime is 15048295931351. The reversal of 15048295931341 is 14313959284051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 15048295931341 - 217 = 15048295800269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15048295931351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242714450475 + ... + 242714450536.

It is an arithmetic number, because the mean of its divisors is an integer number (3883431208096).

Almost surely, 215048295931341 is an apocalyptic number.

It is an amenable number.

15048295931341 is a deficient number, since it is larger than the sum of its proper divisors (485428901043).

15048295931341 is an equidigital number, since it uses as much as digits as its factorization.

15048295931341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 485428901042.

The product of its (nonzero) digits is 4665600, while the sum is 55.

The spelling of 15048295931341 in words is "fifteen trillion, forty-eight billion, two hundred ninety-five million, nine hundred thirty-one thousand, three hundred forty-one".

Divisors: 1 31 485428901011 15048295931341