Base | Representation |
---|---|
bin | 1000110010100010011… |
… | …0111000001001001001 |
3 | 112102202210210200110211 |
4 | 2030220212320021021 |
5 | 4433224303313213 |
6 | 153212032041121 |
7 | 13624022321155 |
oct | 2145046701111 |
9 | 472683720424 |
10 | 151005135433 |
11 | 5904a50a299 |
12 | 253233931a1 |
13 | 11316896c59 |
14 | 7447078065 |
15 | 3ddbe7753d |
hex | 23289b8249 |
151005135433 has 32 divisors (see below), whose sum is σ = 166894940160. Its totient is φ = 135989694720.
The previous prime is 151005135409. The next prime is 151005135443. The reversal of 151005135433 is 334531500151.
It is a cyclic number.
It is not a de Polignac number, because 151005135433 - 25 = 151005135401 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 151005135395 and 151005135404.
It is not an unprimeable number, because it can be changed into a prime (151005135443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 53300785 + ... + 53303617.
It is an arithmetic number, because the mean of its divisors is an integer number (5215466880).
Almost surely, 2151005135433 is an apocalyptic number.
It is an amenable number.
151005135433 is a deficient number, since it is larger than the sum of its proper divisors (15889804727).
151005135433 is a wasteful number, since it uses less digits than its factorization.
151005135433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3589.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 151005135433 its reverse (334531500151), we get a palindrome (485536635584).
The spelling of 151005135433 in words is "one hundred fifty-one billion, five million, one hundred thirty-five thousand, four hundred thirty-three".
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