15102105413 has 4 divisors (see below), whose sum is σ = 15103416588. Its totient is φ = 15100794240.

The previous prime is 15102105401. The next prime is 15102105419. The reversal of 15102105413 is 31450120151.

15102105413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31450120151 = 6173 ⋅5094787.

It can be written as a sum of positive squares in 2 ways, for example, as 5796995044 + 9305110369 = 76138^2 + 96463^2 .

It is a cyclic number.

It is not a de Polignac number, because 15102105413 - 2⁸ = 15102105157 is a prime.

It is a super-3 number, since 3×15102105413³ (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15102105419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 638156 + ... + 661397.

It is an arithmetic number, because the mean of its divisors is an integer number (3775854147).

Almost surely, 2^15102105413 is an apocalyptic number.

It is an amenable number.

15102105413 is a deficient number, since it is larger than the sum of its proper divisors (1311175).

15102105413 is a wasteful number, since it uses less digits than its factorization.

15102105413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1311174.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 15102105413 its reverse (31450120151), we get a palindrome (46552225564).

The spelling of 15102105413 in words is "fifteen billion, one hundred two million, one hundred five thousand, four hundred thirteen".