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15104423103423 = 35034807701141
BaseRepresentation
bin1101101111001100010111…
…0001100000101110111111
31222110222011012211122201120
43123303011301200232333
53434432324303302143
652042513131042023
73116154454006263
oct333630561405677
958428135748646
1015104423103423
1148a3828085755
12183b4088a0313
138574581c1084
143a30b51460a3
151b2d79d4d383
hexdbcc5c60bbf

15104423103423 has 4 divisors (see below), whose sum is σ = 20139230804568. Its totient is φ = 10069615402280.

The previous prime is 15104423103421. The next prime is 15104423103431. The reversal of 15104423103423 is 32430132440151.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 15104423103423 - 21 = 15104423103421 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15104423103421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2517403850568 + ... + 2517403850573.

It is an arithmetic number, because the mean of its divisors is an integer number (5034807701142).

Almost surely, 215104423103423 is an apocalyptic number.

15104423103423 is a deficient number, since it is larger than the sum of its proper divisors (5034807701145).

15104423103423 is an equidigital number, since it uses as much as digits as its factorization.

15104423103423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5034807701144.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 15104423103423 its reverse (32430132440151), we get a palindrome (47534555543574).

The spelling of 15104423103423 in words is "fifteen trillion, one hundred four billion, four hundred twenty-three million, one hundred three thousand, four hundred twenty-three".

Divisors: 1 3 5034807701141 15104423103423