Search a number
-
+
151054142503 = 113113489213
BaseRepresentation
bin1000110010101110000…
…1110100110000100111
3112102220020000111112111
42030223201310300213
54433324330030003
6153220542301451
713625156012005
oct2145341646047
9472806014474
10151054142503
1159075142000
1225337887887
1311323a95414
14744d793a75
153de1407e6d
hex232b874c27

151054142503 has 8 divisors (see below), whose sum is σ = 166148209296. Its totient is φ = 137321946520.

The previous prime is 151054142501. The next prime is 151054142567. The reversal of 151054142503 is 305241450151.

It is not a de Polignac number, because 151054142503 - 21 = 151054142501 is a prime.

It is a super-2 number, since 2×1510541425032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (151054142501) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56743276 + ... + 56745937.

It is an arithmetic number, because the mean of its divisors is an integer number (20768526162).

Almost surely, 2151054142503 is an apocalyptic number.

151054142503 is a deficient number, since it is larger than the sum of its proper divisors (15094066793).

151054142503 is an equidigital number, since it uses as much as digits as its factorization.

151054142503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113489246 (or 113489224 counting only the distinct ones).

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 151054142503 its reverse (305241450151), we get a palindrome (456295592654).

The spelling of 151054142503 in words is "one hundred fifty-one billion, fifty-four million, one hundred forty-two thousand, five hundred three".

Divisors: 1 11 121 1331 113489213 1248381343 13732194773 151054142503