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15106121207 = 31148572737
BaseRepresentation
bin11100001000110010…
…10001110111110111
31102222202211110121122
432010121101313313
5221414131334312
610534544334155
71043225624462
oct160431216767
942882743548
1015106121207
1164520144a1
122b1701435b
131569823a78
14a3436a2d9
155d62c7b72
hex384651df7

15106121207 has 4 divisors (see below), whose sum is σ = 15154694256. Its totient is φ = 15057548160.

The previous prime is 15106121203. The next prime is 15106121269. The reversal of 15106121207 is 70212160151.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 15106121207 - 22 = 15106121203 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15106121203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24286058 + ... + 24286679.

It is an arithmetic number, because the mean of its divisors is an integer number (3788673564).

Almost surely, 215106121207 is an apocalyptic number.

15106121207 is a deficient number, since it is larger than the sum of its proper divisors (48573049).

15106121207 is an equidigital number, since it uses as much as digits as its factorization.

15106121207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48573048.

The product of its (nonzero) digits is 840, while the sum is 26.

Adding to 15106121207 its reverse (70212160151), we get a palindrome (85318281358).

The spelling of 15106121207 in words is "fifteen billion, one hundred six million, one hundred twenty-one thousand, two hundred seven".

Divisors: 1 311 48572737 15106121207