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151121114 = 275560557
BaseRepresentation
bin10010000000111…
…10110011011010
3101112100202012022
421000132303122
5302141333424
622555014442
73513336224
oct1100366332
9345322168
10151121114
1178338591
124273a422
13254022a1
14160db414
15d40195e
hex901ecda

151121114 has 4 divisors (see below), whose sum is σ = 226681674. Its totient is φ = 75560556.

The previous prime is 151121083. The next prime is 151121119. The reversal of 151121114 is 411121151.

151121114 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 126450025 + 24671089 = 11245^2 + 4967^2 .

It is a junction number, because it is equal to n+sod(n) for n = 151121092 and 151121101.

It is not an unprimeable number, because it can be changed into a prime (151121119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37780277 + ... + 37780280.

Almost surely, 2151121114 is an apocalyptic number.

151121114 is a deficient number, since it is larger than the sum of its proper divisors (75560560).

151121114 is an equidigital number, since it uses as much as digits as its factorization.

151121114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75560559.

The product of its digits is 40, while the sum is 17.

The square root of 151121114 is about 12293.1327984367. The cubic root of 151121114 is about 532.6497351991.

Adding to 151121114 its reverse (411121151), we get a palindrome (562242265).

The spelling of 151121114 in words is "one hundred fifty-one million, one hundred twenty-one thousand, one hundred fourteen".

Divisors: 1 2 75560557 151121114