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15113995981 = 72159142283
BaseRepresentation
bin11100001001101110…
…10100011011001101
31110000022122112202221
432010313110123031
5221423140332411
610535425215341
71043352563140
oct160467243315
943008575687
1015113995981
116456502977
122b19791551
13156b3501b6
14a3541a057
155d6d31071
hex384dd46cd

15113995981 has 4 divisors (see below), whose sum is σ = 17273138272. Its totient is φ = 12954853692.

The previous prime is 15113995973. The next prime is 15113996017. The reversal of 15113995981 is 18959931151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 15113995981 - 23 = 15113995973 is a prime.

It is a super-2 number, since 2×151139959812 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15113995921) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1079571135 + ... + 1079571148.

It is an arithmetic number, because the mean of its divisors is an integer number (4318284568).

Almost surely, 215113995981 is an apocalyptic number.

It is an amenable number.

15113995981 is a deficient number, since it is larger than the sum of its proper divisors (2159142291).

15113995981 is an equidigital number, since it uses as much as digits as its factorization.

15113995981 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2159142290.

The product of its digits is 437400, while the sum is 52.

The spelling of 15113995981 in words is "fifteen billion, one hundred thirteen million, nine hundred ninety-five thousand, nine hundred eighty-one".

Divisors: 1 7 2159142283 15113995981