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15114010023 = 33779968307
BaseRepresentation
bin11100001001101110…
…10111110110100111
31110000022200021001000
432010313113312213
5221423141310043
610535425404343
71043352652110
oct160467276647
943008607030
1015114010023
116456512482
122b197996b3
13156b3566c8
14a35421207
155d6d352d3
hex384dd7da7

15114010023 has 16 divisors (see below), whose sum is σ = 25589858560. Its totient is φ = 8636577048.

The previous prime is 15114010019. The next prime is 15114010027. The reversal of 15114010023 is 32001041151.

It is an interprime number because it is at equal distance from previous prime (15114010019) and next prime (15114010027).

It is not a de Polignac number, because 15114010023 - 22 = 15114010019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15114009978 and 15114010005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15114010027) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39983965 + ... + 39984342.

It is an arithmetic number, because the mean of its divisors is an integer number (1599366160).

Almost surely, 215114010023 is an apocalyptic number.

15114010023 is a deficient number, since it is larger than the sum of its proper divisors (10475848537).

15114010023 is an equidigital number, since it uses as much as digits as its factorization.

15114010023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79968323 (or 79968317 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

Adding to 15114010023 its reverse (32001041151), we get a palindrome (47115051174).

The spelling of 15114010023 in words is "fifteen billion, one hundred fourteen million, ten thousand, twenty-three".

Divisors: 1 3 7 9 21 27 63 189 79968307 239904921 559778149 719714763 1679334447 2159144289 5038003341 15114010023