Base | Representation |
---|---|
bin | 11100001001101111… |
… | …10101111110101111 |
3 | 1110000022220112022101 |
4 | 32010313311332233 |
5 | 221423204232143 |
6 | 10535432155531 |
7 | 1043354004634 |
oct | 160467657657 |
9 | 43008815271 |
10 | 15114133423 |
11 | 6456597164 |
12 | 2b19838ba7 |
13 | 156b39a91c |
14 | a3545418b |
15 | 5d6d5bb4d |
hex | 384df5faf |
15114133423 has 4 divisors (see below), whose sum is σ = 15114391960. Its totient is φ = 15113874888.
The previous prime is 15114133417. The next prime is 15114133439. The reversal of 15114133423 is 32433141151.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15114133423 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 15114133391 and 15114133400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15114133123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4708 + ... + 173926.
It is an arithmetic number, because the mean of its divisors is an integer number (3778597990).
Almost surely, 215114133423 is an apocalyptic number.
15114133423 is a deficient number, since it is larger than the sum of its proper divisors (258537).
15114133423 is an equidigital number, since it uses as much as digits as its factorization.
15114133423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 258536.
The product of its digits is 4320, while the sum is 28.
Adding to 15114133423 its reverse (32433141151), we get a palindrome (47547274574).
The spelling of 15114133423 in words is "fifteen billion, one hundred fourteen million, one hundred thirty-three thousand, four hundred twenty-three".
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