Base | Representation |
---|---|
bin | 1101101111110100001011… |
… | …1001011000111010011011 |
3 | 1222111222202011100211021021 |
4 | 3123331002321120322123 |
5 | 3440121222214131011 |
6 | 52051441532423311 |
7 | 3120013400211010 |
oct | 333750271307233 |
9 | 58458664324237 |
10 | 15115112255131 |
11 | 48a83128aa629 |
12 | 18414b0617b37 |
13 | 85846c8bcc05 |
14 | 3a380aa1b707 |
15 | 1b32a3489471 |
hex | dbf42e58e9b |
15115112255131 has 8 divisors (see below), whose sum is σ = 17274839986944. Its totient is φ = 12955491018600.
The previous prime is 15115112255119. The next prime is 15115112255179. The reversal of 15115112255131 is 13155221151151.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 15115112255131 - 215 = 15115112222363 is a prime.
It is a super-2 number, since 2×151151122551312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15115112250131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26319445 + ... + 26887606.
It is an arithmetic number, because the mean of its divisors is an integer number (2159354998368).
Almost surely, 215115112255131 is an apocalyptic number.
15115112255131 is a deficient number, since it is larger than the sum of its proper divisors (2159727731813).
15115112255131 is an equidigital number, since it uses as much as digits as its factorization.
15115112255131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53247641.
The product of its digits is 7500, while the sum is 34.
The spelling of 15115112255131 in words is "fifteen trillion, one hundred fifteen billion, one hundred twelve million, two hundred fifty-five thousand, one hundred thirty-one".
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