Base | Representation |
---|---|
bin | 10010000001101… |
… | …00100000100111 |
3 | 101112112021011020 |
4 | 21000310200213 |
5 | 302202210043 |
6 | 23000542223 |
7 | 3514156356 |
oct | 1100644047 |
9 | 345467136 |
10 | 151210023 |
11 | 78399368 |
12 | 42781973 |
13 | 254338b3 |
14 | 1612199d |
15 | d41ce83 |
hex | 9034827 |
151210023 has 4 divisors (see below), whose sum is σ = 201613368. Its totient is φ = 100806680.
The previous prime is 151209991. The next prime is 151210039. The reversal of 151210023 is 320012151.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 320012151 = 3 ⋅106670717.
It is a cyclic number.
It is not a de Polignac number, because 151210023 - 25 = 151209991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 151209984 and 151210011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (151210063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25201668 + ... + 25201673.
It is an arithmetic number, because the mean of its divisors is an integer number (50403342).
Almost surely, 2151210023 is an apocalyptic number.
151210023 is a deficient number, since it is larger than the sum of its proper divisors (50403345).
151210023 is an equidigital number, since it uses as much as digits as its factorization.
151210023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50403344.
The product of its (nonzero) digits is 60, while the sum is 15.
The square root of 151210023 is about 12296.7484726654. The cubic root of 151210023 is about 532.7541725603.
Adding to 151210023 its reverse (320012151), we get a palindrome (471222174).
The spelling of 151210023 in words is "one hundred fifty-one million, two hundred ten thousand, twenty-three".
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