Base | Representation |
---|---|
bin | 11100001011101000… |
… | …11010100000111001 |
3 | 1110001102210020012220 |
4 | 32011310122200321 |
5 | 221441240333310 |
6 | 10541200354253 |
7 | 1043635656204 |
oct | 160564324071 |
9 | 43042706186 |
10 | 15130011705 |
11 | 6464551806 |
12 | 2b23015989 |
13 | 1571769c63 |
14 | a375c893b |
15 | 5d8446670 |
hex | 385d1a839 |
15130011705 has 8 divisors (see below), whose sum is σ = 24208018752. Its totient is φ = 8069339568.
The previous prime is 15130011697. The next prime is 15130011727. The reversal of 15130011705 is 50711003151.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 15130011705 - 23 = 15130011697 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 504333709 + ... + 504333738.
It is an arithmetic number, because the mean of its divisors is an integer number (3026002344).
Almost surely, 215130011705 is an apocalyptic number.
15130011705 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
15130011705 is a deficient number, since it is larger than the sum of its proper divisors (9078007047).
15130011705 is a wasteful number, since it uses less digits than its factorization.
15130011705 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1008667455.
The product of its (nonzero) digits is 525, while the sum is 24.
Adding to 15130011705 its reverse (50711003151), we get a palindrome (65841014856).
The spelling of 15130011705 in words is "fifteen billion, one hundred thirty million, eleven thousand, seven hundred five".
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