Base | Representation |
---|---|
bin | 1101110000101011110000… |
… | …0110001011111111110011 |
3 | 1222120102020211202222121121 |
4 | 3130022330012023333303 |
5 | 3440342300310230443 |
6 | 52102350131403111 |
7 | 3121052155524001 |
oct | 334127406137763 |
9 | 58512224688547 |
10 | 15130030555123 |
11 | 490367889a180 |
12 | 1844374753497 |
13 | 8599a9531b63 |
14 | 3a4424055a71 |
15 | 1b38780114ed |
hex | dc2bc18bff3 |
15130030555123 has 16 divisors (see below), whose sum is σ = 16836873318144. Its totient is φ = 13480502888160.
The previous prime is 15130030555109. The next prime is 15130030555181. The reversal of 15130030555123 is 32155503003151.
It is not a de Polignac number, because 15130030555123 - 217 = 15130030424051 is a prime.
It is a super-3 number, since 3×151300305551233 (a number of 41 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (15130030555183) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51959415 + ... + 52249792.
It is an arithmetic number, because the mean of its divisors is an integer number (1052304582384).
Almost surely, 215130030555123 is an apocalyptic number.
15130030555123 is a deficient number, since it is larger than the sum of its proper divisors (1706842763021).
15130030555123 is a wasteful number, since it uses less digits than its factorization.
15130030555123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104209482.
The product of its (nonzero) digits is 33750, while the sum is 34.
Adding to 15130030555123 its reverse (32155503003151), we get a palindrome (47285533558274).
The spelling of 15130030555123 in words is "fifteen trillion, one hundred thirty billion, thirty million, five hundred fifty-five thousand, one hundred twenty-three".
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