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15130030555123 = 1167197104209207
BaseRepresentation
bin1101110000101011110000…
…0110001011111111110011
31222120102020211202222121121
43130022330012023333303
53440342300310230443
652102350131403111
73121052155524001
oct334127406137763
958512224688547
1015130030555123
11490367889a180
121844374753497
138599a9531b63
143a4424055a71
151b38780114ed
hexdc2bc18bff3

15130030555123 has 16 divisors (see below), whose sum is σ = 16836873318144. Its totient is φ = 13480502888160.

The previous prime is 15130030555109. The next prime is 15130030555181. The reversal of 15130030555123 is 32155503003151.

It is not a de Polignac number, because 15130030555123 - 217 = 15130030424051 is a prime.

It is a super-3 number, since 3×151300305551233 (a number of 41 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (15130030555183) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51959415 + ... + 52249792.

It is an arithmetic number, because the mean of its divisors is an integer number (1052304582384).

Almost surely, 215130030555123 is an apocalyptic number.

15130030555123 is a deficient number, since it is larger than the sum of its proper divisors (1706842763021).

15130030555123 is a wasteful number, since it uses less digits than its factorization.

15130030555123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104209482.

The product of its (nonzero) digits is 33750, while the sum is 34.

Adding to 15130030555123 its reverse (32155503003151), we get a palindrome (47285533558274).

The spelling of 15130030555123 in words is "fifteen trillion, one hundred thirty billion, thirty million, five hundred fifty-five thousand, one hundred twenty-three".

Divisors: 1 11 67 197 737 2167 13199 145189 104209207 1146301277 6982016869 20529213779 76802185559 225821351569 1375457323193 15130030555123