Base | Representation |
---|---|
bin | 1101110000101111110010… |
… | …0010000100011100011011 |
3 | 1222120112001011222001200120 |
4 | 3130023330202010130123 |
5 | 3440402004032343133 |
6 | 52103045310204323 |
7 | 3121121023355646 |
oct | 334137442043433 |
9 | 58515034861616 |
10 | 15131111606043 |
11 | 4904083041794 |
12 | 18446167b36a3 |
13 | 859b1c4a9864 |
14 | 3a44c7860a5d |
15 | 1b38dcda2ab3 |
hex | dc2fc88471b |
15131111606043 has 16 divisors (see below), whose sum is σ = 20207240856576. Its totient is φ = 10071195765120.
The previous prime is 15131111605943. The next prime is 15131111606057. The reversal of 15131111606043 is 34060611113151.
15131111606043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 15131111606043 - 216 = 15131111540507 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15131111605995 and 15131111606013.
It is not an unprimeable number, because it can be changed into a prime (15131111606243) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 160814430 + ... + 160908492.
It is an arithmetic number, because the mean of its divisors is an integer number (1262952553536).
Almost surely, 215131111606043 is an apocalyptic number.
15131111606043 is a deficient number, since it is larger than the sum of its proper divisors (5076129250533).
15131111606043 is an equidigital number, since it uses as much as digits as its factorization.
15131111606043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179674.
The product of its (nonzero) digits is 6480, while the sum is 33.
Adding to 15131111606043 its reverse (34060611113151), we get a palindrome (49191722719194).
The spelling of 15131111606043 in words is "fifteen trillion, one hundred thirty-one billion, one hundred eleven million, six hundred six thousand, forty-three".
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