Base | Representation |
---|---|
bin | 10110000001010010011… |
… | …011011110110100011111 |
3 | 12100122212022021000102201 |
4 | 112001102123132310133 |
5 | 144243024111032111 |
6 | 3115054300232331 |
7 | 214216534610536 |
oct | 26012233366437 |
9 | 5318768230381 |
10 | 1513211424031 |
11 | 53382744384a |
12 | 20532b53b6a7 |
13 | ac906542388 |
14 | 5335010d31d |
15 | 295671606c1 |
hex | 160526ded1f |
1513211424031 has 4 divisors (see below), whose sum is σ = 1513233038632. Its totient is φ = 1513189809432.
The previous prime is 1513211423959. The next prime is 1513211424037. The reversal of 1513211424031 is 1304241123151.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1513211424031 - 217 = 1513211292959 is a prime.
It is a super-2 number, since 2×15132114240312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1513211424037) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10701945 + ... + 10842418.
It is an arithmetic number, because the mean of its divisors is an integer number (378308259658).
Almost surely, 21513211424031 is an apocalyptic number.
1513211424031 is a deficient number, since it is larger than the sum of its proper divisors (21614601).
1513211424031 is an equidigital number, since it uses as much as digits as its factorization.
1513211424031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21614600.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 1513211424031 its reverse (1304241123151), we get a palindrome (2817452547182).
The spelling of 1513211424031 in words is "one trillion, five hundred thirteen billion, two hundred eleven million, four hundred twenty-four thousand, thirty-one".
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