Base | Representation |
---|---|
bin | 1000110011110000011… |
… | …0100101011110110111 |
3 | 112110121121021000220011 |
4 | 2030330012211132313 |
5 | 4434412021332321 |
6 | 153304314321051 |
7 | 13635103413106 |
oct | 2147406453667 |
9 | 473547230804 |
10 | 151332214711 |
11 | 591a80a9847 |
12 | 253b4a29187 |
13 | 113695864a2 |
14 | 747869a03d |
15 | 3e0aa34ae1 |
hex | 233c1a57b7 |
151332214711 has 4 divisors (see below), whose sum is σ = 160234109712. Its totient is φ = 142430319712.
The previous prime is 151332214703. The next prime is 151332214717. The reversal of 151332214711 is 117412233151.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 117412233151 = 181 ⋅648686371.
It is a cyclic number.
It is not a de Polignac number, because 151332214711 - 23 = 151332214703 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (151332214717) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4450947475 + ... + 4450947508.
It is an arithmetic number, because the mean of its divisors is an integer number (40058527428).
Almost surely, 2151332214711 is an apocalyptic number.
151332214711 is a deficient number, since it is larger than the sum of its proper divisors (8901895001).
151332214711 is an equidigital number, since it uses as much as digits as its factorization.
151332214711 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8901895000.
The product of its digits is 5040, while the sum is 31.
Adding to 151332214711 its reverse (117412233151), we get a palindrome (268744447862).
The spelling of 151332214711 in words is "one hundred fifty-one billion, three hundred thirty-two million, two hundred fourteen thousand, seven hundred eleven".
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