Base | Representation |
---|---|
bin | 1000110011110010010… |
… | …0110111110100010101 |
3 | 112110122011012101201211 |
4 | 2030330210313310111 |
5 | 4434421034413013 |
6 | 153305200421421 |
7 | 13635231041110 |
oct | 2147444676425 |
9 | 473564171654 |
10 | 151340154133 |
11 | 59201631853 |
12 | 253b7617871 |
13 | 1136b10617c |
14 | 7479765577 |
15 | 3e0b5a223d |
hex | 233c937d15 |
151340154133 has 8 divisors (see below), whose sum is σ = 175044034368. Its totient is φ = 128157238464.
The previous prime is 151340154127. The next prime is 151340154143. The reversal of 151340154133 is 331451043151.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 151340154133 - 25 = 151340154101 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 151340154095 and 151340154104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (151340154143) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 130240516 + ... + 130241677.
It is an arithmetic number, because the mean of its divisors is an integer number (21880504296).
Almost surely, 2151340154133 is an apocalyptic number.
It is an amenable number.
151340154133 is a deficient number, since it is larger than the sum of its proper divisors (23703880235).
151340154133 is an equidigital number, since it uses as much as digits as its factorization.
151340154133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 260482283.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 151340154133 its reverse (331451043151), we get a palindrome (482791197284).
The spelling of 151340154133 in words is "one hundred fifty-one billion, three hundred forty million, one hundred fifty-four thousand, one hundred thirty-three".
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