Base | Representation |
---|---|
bin | 1000110011110101011… |
… | …1001100011000001111 |
3 | 112110200002000120221212 |
4 | 2030331113030120033 |
5 | 4434432424024201 |
6 | 153310351245035 |
7 | 13635451132052 |
oct | 2147527143017 |
9 | 473602016855 |
10 | 151353345551 |
11 | 59209021751 |
12 | 253bbb1977b |
13 | 11370a74545 |
14 | 747b3daa99 |
15 | 3e0c80aabb |
hex | 233d5cc60f |
151353345551 has 4 divisors (see below), whose sum is σ = 151384119600. Its totient is φ = 151322571504.
The previous prime is 151353345547. The next prime is 151353345581. The reversal of 151353345551 is 155543353151.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 151353345551 - 22 = 151353345547 is a prime.
It is a super-2 number, since 2×1513533455512 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 151353345499 and 151353345508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (151353345581) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15379646 + ... + 15389483.
It is an arithmetic number, because the mean of its divisors is an integer number (37846029900).
Almost surely, 2151353345551 is an apocalyptic number.
151353345551 is a deficient number, since it is larger than the sum of its proper divisors (30774049).
151353345551 is an equidigital number, since it uses as much as digits as its factorization.
151353345551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30774048.
The product of its digits is 337500, while the sum is 41.
The spelling of 151353345551 in words is "one hundred fifty-one billion, three hundred fifty-three million, three hundred forty-five thousand, five hundred fifty-one".
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