Base | Representation |
---|---|
bin | 11100001100110101… |
… | …00100010001011001 |
3 | 1110002010121100121121 |
4 | 32012122210101121 |
5 | 222001320410040 |
6 | 10542155005241 |
7 | 1044116663005 |
oct | 160632442131 |
9 | 43063540547 |
10 | 15140013145 |
11 | 646a162a64 |
12 | 2b26439821 |
13 | 157385c37a |
14 | a38a6d705 |
15 | 5d926ec4a |
hex | 3866a4459 |
15140013145 has 4 divisors (see below), whose sum is σ = 18168015780. Its totient is φ = 12112010512.
The previous prime is 15140013139. The next prime is 15140013167. The reversal of 15140013145 is 54131004151.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54131004151 = 7 ⋅7733000593.
It can be written as a sum of positive squares in 2 ways, for example, as 12000764304 + 3139248841 = 109548^2 + 56029^2 .
It is a cyclic number.
It is not a de Polignac number, because 15140013145 - 227 = 15005795417 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1514001310 + ... + 1514001319.
It is an arithmetic number, because the mean of its divisors is an integer number (4542003945).
Almost surely, 215140013145 is an apocalyptic number.
It is an amenable number.
15140013145 is a deficient number, since it is larger than the sum of its proper divisors (3028002635).
15140013145 is an equidigital number, since it uses as much as digits as its factorization.
15140013145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3028002634.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 15140013145 its reverse (54131004151), we get a palindrome (69271017296).
The spelling of 15140013145 in words is "fifteen billion, one hundred forty million, thirteen thousand, one hundred forty-five".
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