Base | Representation |
---|---|
bin | 11100001110011000… |
… | …01011111000010001 |
3 | 1110010001002012021000 |
4 | 32013030023320101 |
5 | 222013133123213 |
6 | 10543341452213 |
7 | 1044335356065 |
oct | 160714137021 |
9 | 43101065230 |
10 | 15153020433 |
11 | 6476537591 |
12 | 2b2a871069 |
13 | 15764649a5 |
14 | a3a697aa5 |
15 | 5da48dc73 |
hex | 38730be11 |
15153020433 has 32 divisors (see below), whose sum is σ = 22854424320. Its totient is φ = 9920655360.
The previous prime is 15153020423. The next prime is 15153020437. The reversal of 15153020433 is 33402035151.
It is not a de Polignac number, because 15153020433 - 212 = 15153016337 is a prime.
It is a super-2 number, since 2×151530204332 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 15153020397 and 15153020406.
It is not an unprimeable number, because it can be changed into a prime (15153020437) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 477291 + ... + 508047.
It is an arithmetic number, because the mean of its divisors is an integer number (714200760).
Almost surely, 215153020433 is an apocalyptic number.
It is an amenable number.
15153020433 is a deficient number, since it is larger than the sum of its proper divisors (7701403887).
15153020433 is a wasteful number, since it uses less digits than its factorization.
15153020433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31094 (or 31088 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
Adding to 15153020433 its reverse (33402035151), we get a palindrome (48555055584).
The spelling of 15153020433 in words is "fifteen billion, one hundred fifty-three million, twenty thousand, four hundred thirty-three".
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