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152014703 = 367414209
BaseRepresentation
bin10010000111110…
…00111101101111
3101121001010222012
421003320331233
5302403432303
623030111435
73524050361
oct1103707557
9347033865
10152014703
1178898995
1242aab57b
1325655c39
1416290d31
15d52b5d8
hex90f8f6f

152014703 has 4 divisors (see below), whose sum is σ = 152429280. Its totient is φ = 151600128.

The previous prime is 152014693. The next prime is 152014711. The reversal of 152014703 is 307410251.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152014703 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (152014783) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206738 + ... + 207471.

It is an arithmetic number, because the mean of its divisors is an integer number (38107320).

Almost surely, 2152014703 is an apocalyptic number.

152014703 is a deficient number, since it is larger than the sum of its proper divisors (414577).

152014703 is an equidigital number, since it uses as much as digits as its factorization.

152014703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 414576.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 152014703 is about 12329.4242769077. The cubic root of 152014703 is about 533.6975368692.

Adding to 152014703 its reverse (307410251), we get a palindrome (459424954).

The spelling of 152014703 in words is "one hundred fifty-two million, fourteen thousand, seven hundred three".

Divisors: 1 367 414209 152014703