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152127140127 = 364439786931
BaseRepresentation
bin1000110110101101111…
…0111111000100011111
3112112200000001102120020
42031223132333010133
54443024021441002
6153515232323223
713663565232654
oct2155336770437
9475600042506
10152127140127
1159575893aa6
12255970a3513
1311465180661
1475120a3c2b
153e557082bc
hex236b7bf11f

152127140127 has 8 divisors (see below), whose sum is σ = 202839592320. Its totient is φ = 101416390680.

The previous prime is 152127140107. The next prime is 152127140183. The reversal of 152127140127 is 721041721251.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 152127140127 - 216 = 152127074591 is a prime.

It is a super-2 number, since 2×1521271401272 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (152127140107) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 200149 + ... + 586782.

It is an arithmetic number, because the mean of its divisors is an integer number (25354949040).

Almost surely, 2152127140127 is an apocalyptic number.

152127140127 is a deficient number, since it is larger than the sum of its proper divisors (50712452193).

152127140127 is an equidigital number, since it uses as much as digits as its factorization.

152127140127 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 851373.

The product of its (nonzero) digits is 7840, while the sum is 33.

Adding to 152127140127 its reverse (721041721251), we get a palindrome (873168861378).

The spelling of 152127140127 in words is "one hundred fifty-two billion, one hundred twenty-seven million, one hundred forty thousand, one hundred twenty-seven".

Divisors: 1 3 64439 193317 786931 2360793 50709046709 152127140127