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152133535 = 530426707
BaseRepresentation
bin10010001000101…
…01111110011111
3101121021011222101
421010111332133
5302421233120
623032425531
73525054001
oct1104257637
9347234871
10152133535
117896a1a4
1242b482a7
1325698058
14162c2371
15d55190a
hex9115f9f

152133535 has 4 divisors (see below), whose sum is σ = 182560248. Its totient is φ = 121706824.

The previous prime is 152133503. The next prime is 152133547. The reversal of 152133535 is 535331251.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 152133535 - 25 = 152133503 is a prime.

It is a super-2 number, since 2×1521335352 = 46289224943192450, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15213349 + ... + 15213358.

It is an arithmetic number, because the mean of its divisors is an integer number (45640062).

Almost surely, 2152133535 is an apocalyptic number.

152133535 is a deficient number, since it is larger than the sum of its proper divisors (30426713).

152133535 is an equidigital number, since it uses as much as digits as its factorization.

152133535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30426712.

The product of its digits is 6750, while the sum is 28.

The square root of 152133535 is about 12334.2423764089. The cubic root of 152133535 is about 533.8365669018.

Adding to 152133535 its reverse (535331251), we get a palindrome (687464786).

The spelling of 152133535 in words is "one hundred fifty-two million, one hundred thirty-three thousand, five hundred thirty-five".

Divisors: 1 5 30426707 152133535