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152153334141 = 350717778047
BaseRepresentation
bin1000110110110100001…
…0111010000101111101
3112112201211100012222220
42031231002322011331
54443102223143031
6153522005555553
713664334000234
oct2155502720575
9475654305886
10152153334141
1159589654a46
12255a3a15bb9
131146a722183
147515761b1b
153e57b7e596
hex236d0ba17d

152153334141 has 4 divisors (see below), whose sum is σ = 202871112192. Its totient is φ = 101435556092.

The previous prime is 152153334127. The next prime is 152153334209. The reversal of 152153334141 is 141433351251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 141433351251 = 347144450417.

It is a cyclic number.

It is not a de Polignac number, because 152153334141 - 213 = 152153325949 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (152153334341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25358889021 + ... + 25358889026.

It is an arithmetic number, because the mean of its divisors is an integer number (50717778048).

Almost surely, 2152153334141 is an apocalyptic number.

It is an amenable number.

152153334141 is a deficient number, since it is larger than the sum of its proper divisors (50717778051).

152153334141 is an equidigital number, since it uses as much as digits as its factorization.

152153334141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50717778050.

The product of its digits is 21600, while the sum is 33.

Adding to 152153334141 its reverse (141433351251), we get a palindrome (293586685392).

The spelling of 152153334141 in words is "one hundred fifty-two billion, one hundred fifty-three million, three hundred thirty-four thousand, one hundred forty-one".

Divisors: 1 3 50717778047 152153334141