Base | Representation |
---|---|
bin | 10110001001011111000… |
… | …100000001110001010111 |
3 | 12101111120201120100202111 |
4 | 112021133010001301113 |
5 | 144414040402023020 |
6 | 3123111523251451 |
7 | 214650623465656 |
oct | 26113704016127 |
9 | 5344521510674 |
10 | 1522013314135 |
11 | 537533923096 |
12 | 206b87219b87 |
13 | b06a9c4a782 |
14 | 539470b519d |
15 | 298cec57d5a |
hex | 1625f101c57 |
1522013314135 has 16 divisors (see below), whose sum is σ = 1827510055776. Its totient is φ = 1216881497088.
The previous prime is 1522013314109. The next prime is 1522013314169. The reversal of 1522013314135 is 5314133102251.
It is a cyclic number.
It is not a de Polignac number, because 1522013314135 - 27 = 1522013314007 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1522013314097 and 1522013314106.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 72649732 + ... + 72670678.
It is an arithmetic number, because the mean of its divisors is an integer number (114219378486).
Almost surely, 21522013314135 is an apocalyptic number.
1522013314135 is a deficient number, since it is larger than the sum of its proper divisors (305496741641).
1522013314135 is a wasteful number, since it uses less digits than its factorization.
1522013314135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28962.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 1522013314135 its reverse (5314133102251), we get a palindrome (6836146416386).
The spelling of 1522013314135 in words is "one trillion, five hundred twenty-two billion, thirteen million, three hundred fourteen thousand, one hundred thirty-five".
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