Base | Representation |
---|---|
bin | 10110001001100000101… |
… | …110001001110000110011 |
3 | 12101111122122220202121201 |
4 | 112021200232021300303 |
5 | 144414120012243011 |
6 | 3123114355432031 |
7 | 214651412114560 |
oct | 26114056116063 |
9 | 5344578822551 |
10 | 1522041134131 |
11 | 5375485a4721 |
12 | 206b945b5617 |
13 | b06b293b3cb |
14 | 5394aa77867 |
15 | 298d2400cc1 |
hex | 16260b89c33 |
1522041134131 has 32 divisors (see below), whose sum is σ = 1902809825280. Its totient is φ = 1189255737600.
The previous prime is 1522041134113. The next prime is 1522041134171. The reversal of 1522041134131 is 1314311402251.
It is not a de Polignac number, because 1522041134131 - 217 = 1522041003059 is a prime.
It is a super-2 number, since 2×15220411341312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1522041134131.
It is not an unprimeable number, because it can be changed into a prime (1522041134101) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2691531 + ... + 3207556.
It is an arithmetic number, because the mean of its divisors is an integer number (59462807040).
Almost surely, 21522041134131 is an apocalyptic number.
1522041134131 is a deficient number, since it is larger than the sum of its proper divisors (380768691149).
1522041134131 is a wasteful number, since it uses less digits than its factorization.
1522041134131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5899195.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 1522041134131 its reverse (1314311402251), we get a palindrome (2836352536382).
The spelling of 1522041134131 in words is "one trillion, five hundred twenty-two billion, forty-one million, one hundred thirty-four thousand, one hundred thirty-one".
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