Base | Representation |
---|---|
bin | 1000110111000100011… |
… | …1010000111010001011 |
3 | 112112220120202201121210 |
4 | 2031301013100322023 |
5 | 4443222211210120 |
6 | 153532444504203 |
7 | 13666123060362 |
oct | 2156107207213 |
9 | 475816681553 |
10 | 152221585035 |
11 | 59614130943 |
12 | 2560284b063 |
13 | 1147b8ca810 |
14 | 752084a7d9 |
15 | 3e5db61ce0 |
hex | 23711d0e8b |
152221585035 has 32 divisors (see below), whose sum is σ = 266735105280. Its totient is φ = 73669684608.
The previous prime is 152221585013. The next prime is 152221585051. The reversal of 152221585035 is 530585122251.
It is a de Polignac number, because none of the positive numbers 2k-152221585035 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a junction number, because it is equal to n+sod(n) for n = 152221584984 and 152221585002.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6603949 + ... + 6626958.
It is an arithmetic number, because the mean of its divisors is an integer number (8335472040).
Almost surely, 2152221585035 is an apocalyptic number.
152221585035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
152221585035 is a deficient number, since it is larger than the sum of its proper divisors (114513520245).
152221585035 is a wasteful number, since it uses less digits than its factorization.
152221585035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13230987.
The product of its (nonzero) digits is 120000, while the sum is 39.
The spelling of 152221585035 in words is "one hundred fifty-two billion, two hundred twenty-one million, five hundred eighty-five thousand, thirty-five".
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