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152242305511 = 272595585029
BaseRepresentation
bin1000110111001001011…
…0010011100111100111
3112112222000202102202211
42031302112103213213
54443243012234021
6153534504544251
713666464150052
oct2156226234747
9475860672684
10152242305511
11596248a34aa
1225609782087
1311482ca3b5a
1475234c1a99
153e608a63e1
hex23725939e7

152242305511 has 4 divisors (see below), whose sum is σ = 152247917800. Its totient is φ = 152236693224.

The previous prime is 152242305493. The next prime is 152242305533. The reversal of 152242305511 is 115503242251.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 152242305511 - 29 = 152242304999 is a prime.

It is a super-2 number, since 2×1522423055112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (152242305581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2765256 + ... + 2819773.

It is an arithmetic number, because the mean of its divisors is an integer number (38061979450).

Almost surely, 2152242305511 is an apocalyptic number.

152242305511 is a deficient number, since it is larger than the sum of its proper divisors (5612289).

152242305511 is an equidigital number, since it uses as much as digits as its factorization.

152242305511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5612288.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 152242305511 its reverse (115503242251), we get a palindrome (267745547762).

The spelling of 152242305511 in words is "one hundred fifty-two billion, two hundred forty-two million, three hundred five thousand, five hundred eleven".

Divisors: 1 27259 5585029 152242305511