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15231044000000 = 2856311131087
BaseRepresentation
bin1101110110100100000011…
…1101111001100100000000
31222221001222122101122212202
43131221000331321210000
53444021134231000000
652221013420212332
73131256316611203
oct335510075714400
958831878348782
1015231044000000
1149424a42a1424
12185ba6599a0a8
13866386ca830a
143a928792393a
151b62db1d5dd5
hexdda40f79900

15231044000000 has 504 divisors, whose sum is σ = 39612212957184. Its totient is φ = 5838336000000.

The previous prime is 15231043999993. The next prime is 15231044000057. The reversal of 15231044000000 is 44013251.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 14011999457 + ... + 14012000543.

Almost surely, 215231044000000 is an apocalyptic number.

15231044000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 15231044000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19806106478592).

15231044000000 is an abundant number, since it is smaller than the sum of its proper divisors (24381168957184).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

15231044000000 is an frugal number, since it uses more digits than its factorization.

15231044000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1277 (or 1238 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 20.

Adding to 15231044000000 its reverse (44013251), we get a palindrome (15231088013251).

The spelling of 15231044000000 in words is "fifteen trillion, two hundred thirty-one billion, forty-four million", and thus it is an aban number.