15252050131 has 4 divisors (see below), whose sum is σ = 15318653200. Its totient is φ = 15185447064.

The previous prime is 15252050117. The next prime is 15252050137. The reversal of 15252050131 is 13105025251.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13105025251 = 2741 ⋅4781111.

It is a cyclic number.

It is not a de Polignac number, because 15252050131 - 2⁹ = 15252049619 is a prime.

It is a super-2 number, since 2×15252050131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 15252050096 and 15252050105.

It is not an unprimeable number, because it can be changed into a prime (15252050137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33301191 + ... + 33301648.

It is an arithmetic number, because the mean of its divisors is an integer number (3829663300).

Almost surely, 2^15252050131 is an apocalyptic number.

15252050131 is a deficient number, since it is larger than the sum of its proper divisors (66603069).

15252050131 is an equidigital number, since it uses as much as digits as its factorization.

15252050131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66603068.

The product of its (nonzero) digits is 1500, while the sum is 25.

Adding to 15252050131 its reverse (13105025251), we get a palindrome (28357075382).

The spelling of 15252050131 in words is "fifteen billion, two hundred fifty-two million, fifty thousand, one hundred thirty-one".