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1525445050103 = 13117341926931
BaseRepresentation
bin10110001100101011100…
…111000011111011110111
312101211102212222121111122
4112030223213003323313
5144443102413100403
63124440233254155
7215131643662052
oct26145347037367
95354385877448
101525445050103
11538a34a65117
1220778456435b
13b0b05c05780
1453b90b83a99
1529a3117d838
hex1632b9c3ef7

1525445050103 has 4 divisors (see below), whose sum is σ = 1642786977048. Its totient is φ = 1408103123160.

The previous prime is 1525445050099. The next prime is 1525445050111. The reversal of 1525445050103 is 3010505445251.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1525445050103 - 22 = 1525445050099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1525445050183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58670963453 + ... + 58670963478.

It is an arithmetic number, because the mean of its divisors is an integer number (410696744262).

Almost surely, 21525445050103 is an apocalyptic number.

1525445050103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1525445050103 is a deficient number, since it is larger than the sum of its proper divisors (117341926945).

1525445050103 is a wasteful number, since it uses less digits than its factorization.

1525445050103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 117341926944.

The product of its (nonzero) digits is 60000, while the sum is 35.

The spelling of 1525445050103 in words is "one trillion, five hundred twenty-five billion, four hundred forty-five million, fifty thousand, one hundred three".

Divisors: 1 13 117341926931 1525445050103