Base | Representation |
---|---|
bin | 1101110111111101101110… |
… | …1110001111011000110111 |
3 | 2000000101010012121022200201 |
4 | 3131333123232033120313 |
5 | 3444414433442400210 |
6 | 52240034141421331 |
7 | 3133100655464053 |
oct | 335773356173067 |
9 | 60011105538621 |
10 | 15255115200055 |
11 | 4951726915295 |
12 | 186466326a847 |
13 | 868721c73463 |
14 | 3aa4cc7b4c63 |
15 | 1b6c4958d53a |
hex | ddfdbb8f637 |
15255115200055 has 8 divisors (see below), whose sum is σ = 18487387134144. Its totient is φ = 12083259564000.
The previous prime is 15255115200041. The next prime is 15255115200089. The reversal of 15255115200055 is 55000251155251.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 15255115200055 - 211 = 15255115198007 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 15255115199987 and 15255115200023.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15104073951 + ... + 15104074960.
It is an arithmetic number, because the mean of its divisors is an integer number (2310923391768).
Almost surely, 215255115200055 is an apocalyptic number.
15255115200055 is a deficient number, since it is larger than the sum of its proper divisors (3232271934089).
15255115200055 is a wasteful number, since it uses less digits than its factorization.
15255115200055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30208149017.
The product of its (nonzero) digits is 62500, while the sum is 37.
The spelling of 15255115200055 in words is "fifteen trillion, two hundred fifty-five billion, one hundred fifteen million, two hundred thousand, fifty-five".
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