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152871401055 = 3510191426737
BaseRepresentation
bin1000111001011111011…
…0000111011001011111
3112121120212111210121210
42032113312013121133
510001040034313210
6154121140355503
714021203316622
oct2162766073137
9477525453553
10152871401055
1159917a1427a
12257643a5b93
1311553418b39
147582c7ddb9
153e9ac1ee20
hex2397d8765f

152871401055 has 8 divisors (see below), whose sum is σ = 244594241712. Its totient is φ = 81531413888.

The previous prime is 152871400963. The next prime is 152871401083. The reversal of 152871401055 is 550104178251.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 152871401055 - 212 = 152871396959 is a prime.

It is a super-2 number, since 2×1528714010552 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5095713354 + ... + 5095713383.

It is an arithmetic number, because the mean of its divisors is an integer number (30574280214).

Almost surely, 2152871401055 is an apocalyptic number.

152871401055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

152871401055 is a deficient number, since it is larger than the sum of its proper divisors (91722840657).

152871401055 is a wasteful number, since it uses less digits than its factorization.

152871401055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10191426745.

The product of its (nonzero) digits is 56000, while the sum is 39.

The spelling of 152871401055 in words is "one hundred fifty-two billion, eight hundred seventy-one million, four hundred one thousand, fifty-five".

Divisors: 1 3 5 15 10191426737 30574280211 50957133685 152871401055