Base | Representation |
---|---|
bin | 11100100000000010… |
… | …01101111010100101 |
3 | 1110111100210110021211 |
4 | 32100001031322211 |
5 | 222314042441013 |
6 | 11010152311421 |
7 | 1051114354666 |
oct | 162001157245 |
9 | 43440713254 |
10 | 15301140133 |
11 | 6542105064 |
12 | 2b703a2571 |
13 | 159b055a96 |
14 | a5221336d |
15 | 5e849b23d |
hex | 39004dea5 |
15301140133 has 4 divisors (see below), whose sum is σ = 15301673100. Its totient is φ = 15300607168.
The previous prime is 15301140083. The next prime is 15301140187. The reversal of 15301140133 is 33104110351.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1169161249 + 14131978884 = 34193^2 + 118878^2 .
It is a cyclic number.
It is not a de Polignac number, because 15301140133 - 221 = 15299042981 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15301140193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220810 + ... + 281707.
It is an arithmetic number, because the mean of its divisors is an integer number (3825418275).
Almost surely, 215301140133 is an apocalyptic number.
It is an amenable number.
15301140133 is a deficient number, since it is larger than the sum of its proper divisors (532967).
15301140133 is an equidigital number, since it uses as much as digits as its factorization.
15301140133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 532966.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 15301140133 its reverse (33104110351), we get a palindrome (48405250484).
The spelling of 15301140133 in words is "fifteen billion, three hundred one million, one hundred forty thousand, one hundred thirty-three".
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