Base | Representation |
---|---|
bin | 10110010001001111100… |
… | …111100100111000110111 |
3 | 12102022002022110202122220 |
4 | 112101033213210320313 |
5 | 200033121044212101 |
6 | 3131010321453423 |
7 | 215364232332102 |
oct | 26211747447067 |
9 | 5368068422586 |
10 | 1530344132151 |
11 | 540019403a5a |
12 | 2087111a1273 |
13 | b1406b8baa3 |
14 | 540d7695739 |
15 | 29c1b2ed636 |
hex | 1644f9e4e37 |
1530344132151 has 4 divisors (see below), whose sum is σ = 2040458842872. Its totient is φ = 1020229421432.
The previous prime is 1530344132143. The next prime is 1530344132153. The reversal of 1530344132151 is 1512314430351.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1530344132151 - 23 = 1530344132143 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1530344132153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255057355356 + ... + 255057355361.
It is an arithmetic number, because the mean of its divisors is an integer number (510114710718).
Almost surely, 21530344132151 is an apocalyptic number.
1530344132151 is a deficient number, since it is larger than the sum of its proper divisors (510114710721).
1530344132151 is an equidigital number, since it uses as much as digits as its factorization.
1530344132151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 510114710720.
The product of its (nonzero) digits is 21600, while the sum is 33.
The spelling of 1530344132151 in words is "one trillion, five hundred thirty billion, three hundred forty-four million, one hundred thirty-two thousand, one hundred fifty-one".
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