153035055031241 has 4 divisors (see below), whose sum is σ = 153213625691412. Its totient is φ = 152856484371072.

The previous prime is 153035055031223. The next prime is 153035055031253. The reversal of 153035055031241 is 142130550530351.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 64989862133641 + 88045192897600 = 8061629^2 + 9383240^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-153035055031241 is a prime.

It is a super-2 number, since 2×153035055031241² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 153035055031195 and 153035055031204.

It is not an unprimeable number, because it can be changed into a prime (153035055231241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89285328800 + ... + 89285330513.

It is an arithmetic number, because the mean of its divisors is an integer number (38303406422853).

Almost surely, 2^{153035055031241} is an apocalyptic number.

It is an amenable number.

153035055031241 is a deficient number, since it is larger than the sum of its proper divisors (178570660171).

153035055031241 is an equidigital number, since it uses as much as digits as its factorization.

153035055031241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 178570660170.

The product of its (nonzero) digits is 135000, while the sum is 38.

The spelling of 153035055031241 in words is "one hundred fifty-three trillion, thirty-five billion, fifty-five million, thirty-one thousand, two hundred forty-one".