Base | Representation |
---|---|
bin | 10110010001111001111… |
… | …101100100011100000111 |
3 | 12102100220211020020210010 |
4 | 112101321331210130013 |
5 | 200041044430244201 |
6 | 3131205020201303 |
7 | 215420646603444 |
oct | 26217175443407 |
9 | 5370824206703 |
10 | 1531054540551 |
11 | 540353412338 |
12 | 20888b099233 |
13 | b14bb1038a3 |
14 | 54163b7c9cb |
15 | 29c5d879bd6 |
hex | 16479f64707 |
1531054540551 has 8 divisors (see below), whose sum is σ = 2048670845424. Its totient is φ = 1017070631360.
The previous prime is 1531054540541. The next prime is 1531054540559. The reversal of 1531054540551 is 1550454501351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1531054540551 - 219 = 1531054016263 is a prime.
It is a super-2 number, since 2×15310545405512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1531054540559) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 908097936 + ... + 908099621.
It is an arithmetic number, because the mean of its divisors is an integer number (256083855678).
Almost surely, 21531054540551 is an apocalyptic number.
1531054540551 is a deficient number, since it is larger than the sum of its proper divisors (517616304873).
1531054540551 is a wasteful number, since it uses less digits than its factorization.
1531054540551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1816197841.
The product of its (nonzero) digits is 150000, while the sum is 39.
The spelling of 1531054540551 in words is "one trillion, five hundred thirty-one billion, fifty-four million, five hundred forty thousand, five hundred fifty-one".
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