Search a number
-
+
15311213401441 = 47351192785673
BaseRepresentation
bin1101111011001110101101…
…1011111001010101100001
32000012201220210021012222011
43132303223123321111201
54001324331112321231
652321512504512521
73140125066356436
oct336635333712541
960181823235864
1015311213401441
1149734a38912a1
1218734ba47b741
13870ac2242b69
143ad0d0d97b8d
151b842e4b79b1
hexdeceb6f9561

15311213401441 has 8 divisors (see below), whose sum is σ = 15641437780224. Its totient is φ = 14981174601120.

The previous prime is 15311213401387. The next prime is 15311213401447. The reversal of 15311213401441 is 14410431211351.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 15311213401441 - 223 = 15311205012833 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15311213401447) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46227820 + ... + 46557853.

It is an arithmetic number, because the mean of its divisors is an integer number (1955179722528).

Almost surely, 215311213401441 is an apocalyptic number.

It is an amenable number.

15311213401441 is a deficient number, since it is larger than the sum of its proper divisors (330224378783).

15311213401441 is an equidigital number, since it uses as much as digits as its factorization.

15311213401441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92789231.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 15311213401441 its reverse (14410431211351), we get a palindrome (29721644612792).

The spelling of 15311213401441 in words is "fifteen trillion, three hundred eleven billion, two hundred thirteen million, four hundred one thousand, four hundred forty-one".

Divisors: 1 47 3511 165017 92785673 4360926631 325770497903 15311213401441