1531200553231 has 4 divisors (see below), whose sum is σ = 1597774490352. Its totient is φ = 1464626616112.

The previous prime is 1531200553177. The next prime is 1531200553261. The reversal of 1531200553231 is 1323550021351.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1531200553231 - 2²⁵ = 1531166998799 is a prime.

It is a super-2 number, since 2×1531200553231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1531200553193 and 1531200553202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1531200553261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33286968526 + ... + 33286968571.

It is an arithmetic number, because the mean of its divisors is an integer number (399443622588).

Almost surely, 2^{1531200553231} is an apocalyptic number.

1531200553231 is a deficient number, since it is larger than the sum of its proper divisors (66573937121).

1531200553231 is an equidigital number, since it uses as much as digits as its factorization.

1531200553231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66573937120.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 1531200553231 its reverse (1323550021351), we get a palindrome (2854750574582).

The spelling of 1531200553231 in words is "one trillion, five hundred thirty-one billion, two hundred million, five hundred fifty-three thousand, two hundred thirty-one".