Base | Representation |
---|---|
bin | 1101111011010010110001… |
… | …1000100010011000110011 |
3 | 2000012211201201121121010201 |
4 | 3132310230120202120303 |
5 | 4001334044034240201 |
6 | 52322212551340031 |
7 | 3140164100216413 |
oct | 336645430423063 |
9 | 60184651547121 |
10 | 15312303040051 |
11 | 4973a02969976 |
12 | 1873763381617 |
13 | 870c36c06634 |
14 | 3ad19599a643 |
15 | 1b8494ea3801 |
hex | ded2c622633 |
15312303040051 has 4 divisors (see below), whose sum is σ = 15312312488704. Its totient is φ = 15312293591400.
The previous prime is 15312303040031. The next prime is 15312303040079. The reversal of 15312303040051 is 15004030321351.
It is a happy number.
15312303040051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 15312303040051 - 231 = 15310155556403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15312303040031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1608435 + ... + 5762956.
It is an arithmetic number, because the mean of its divisors is an integer number (3828078122176).
Almost surely, 215312303040051 is an apocalyptic number.
15312303040051 is a deficient number, since it is larger than the sum of its proper divisors (9448653).
15312303040051 is an equidigital number, since it uses as much as digits as its factorization.
15312303040051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9448652.
The product of its (nonzero) digits is 5400, while the sum is 28.
The spelling of 15312303040051 in words is "fifteen trillion, three hundred twelve billion, three hundred three million, forty thousand, fifty-one".
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