153130012031 has 4 divisors (see below), whose sum is σ = 153131439192. Its totient is φ = 153128584872.

The previous prime is 153130012027. The next prime is 153130012069. The reversal of 153130012031 is 130210031351.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 130210031351 = 547 ⋅238043933.

It is a cyclic number.

It is not a de Polignac number, because 153130012031 - 2² = 153130012027 is a prime.

It is a super-2 number, since 2×153130012031² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 153130011994 and 153130012012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (153130002031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 538280 + ... + 772013.

It is an arithmetic number, because the mean of its divisors is an integer number (38282859798).

Almost surely, 2^153130012031 is an apocalyptic number.

153130012031 is a deficient number, since it is larger than the sum of its proper divisors (1427161).

153130012031 is a wasteful number, since it uses less digits than its factorization.

153130012031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1427160.

The product of its (nonzero) digits is 270, while the sum is 20.

Adding to 153130012031 its reverse (130210031351), we get a palindrome (283340043382).

The spelling of 153130012031 in words is "one hundred fifty-three billion, one hundred thirty million, twelve thousand, thirty-one".