Base | Representation |
---|---|
bin | 1000111010011101010… |
… | …0111010000111010111 |
3 | 112122020222020110121101 |
4 | 2032213110322013113 |
5 | 10002103032200401 |
6 | 154203015330531 |
7 | 14030506066042 |
oct | 2164724720727 |
9 | 478228213541 |
10 | 153131131351 |
11 | 59a40593510 |
12 | 25817380a47 |
13 | 115951873c3 |
14 | 75a956dc59 |
15 | 3eb3927101 |
hex | 23a753a1d7 |
153131131351 has 16 divisors (see below), whose sum is σ = 175893845760. Its totient is φ = 131846158080.
The previous prime is 153131131249. The next prime is 153131131379.
153131131351 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 153131131351 - 227 = 152996913623 is a prime.
It is a super-3 number, since 3×1531311313513 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153131131051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 654670 + ... + 857236.
It is an arithmetic number, because the mean of its divisors is an integer number (10993365360).
Almost surely, 2153131131351 is an apocalyptic number.
153131131351 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
153131131351 is a deficient number, since it is larger than the sum of its proper divisors (22762714409).
153131131351 is a wasteful number, since it uses less digits than its factorization.
153131131351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 206214.
The product of its digits is 2025, while the sum is 28.
It can be divided in two parts, 153131 and 131351, that added together give a palindrome (284482).
The spelling of 153131131351 in words is "one hundred fifty-three billion, one hundred thirty-one million, one hundred thirty-one thousand, three hundred fifty-one".
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