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15313140405213 = 371466814971313
BaseRepresentation
bin1101111011010101111001…
…0010110101001111011101
32000012220220002021011012020
43132311132102311033131
54001342302420431323
652322432023130353
73140223615545310
oct336653622651735
960186802234166
1015313140405213
1149742a26007a2
1218739578a39b9
1387103b53c991
143ad234c90977
151b84e375bae3
hexded5e4b53dd

15313140405213 has 16 divisors (see below), whose sum is σ = 23334472964736. Its totient is φ = 8750304529920.

The previous prime is 15313140405151. The next prime is 15313140405259. The reversal of 15313140405213 is 31250404131351.

It is not a de Polignac number, because 15313140405213 - 213 = 15313140397021 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15313140405413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 594645 + ... + 5565957.

It is an arithmetic number, because the mean of its divisors is an integer number (1458404560296).

Almost surely, 215313140405213 is an apocalyptic number.

It is an amenable number.

15313140405213 is a deficient number, since it is larger than the sum of its proper divisors (8021332559523).

15313140405213 is a wasteful number, since it uses less digits than its factorization.

15313140405213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5118004.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 15313140405213 its reverse (31250404131351), we get a palindrome (46563544536564).

The spelling of 15313140405213 in words is "fifteen trillion, three hundred thirteen billion, one hundred forty million, four hundred five thousand, two hundred thirteen".

Divisors: 1 3 7 21 146681 440043 1026767 3080301 4971313 14913939 34799191 104397573 729197162153 2187591486459 5104380135071 15313140405213