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1531314242113 = 19209567384581
BaseRepresentation
bin10110010010001001011…
…100010000001001000001
312102101120220220110100111
4112102021130100021001
5200042112421221423
63131250454351321
7215430252203035
oct26221134201101
95371526813314
101531314242113
11540476a71a27
1220894205b541
13b152cb62056
145418a4621c5
1529c7657860d
hex16489710241

1531314242113 has 8 divisors (see below), whose sum is σ = 1611921611520. Its totient is φ = 1450708061040.

The previous prime is 1531314242033. The next prime is 1531314242119. The reversal of 1531314242113 is 3112424131351.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1531314242113 - 213 = 1531314233921 is a prime.

It is a super-2 number, since 2×15313142421132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1531314242119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3789483 + ... + 4174063.

It is an arithmetic number, because the mean of its divisors is an integer number (201490201440).

Almost surely, 21531314242113 is an apocalyptic number.

It is an amenable number.

1531314242113 is a deficient number, since it is larger than the sum of its proper divisors (80607369407).

1531314242113 is a wasteful number, since it uses less digits than its factorization.

1531314242113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 594167.

The product of its digits is 8640, while the sum is 31.

Adding to 1531314242113 its reverse (3112424131351), we get a palindrome (4643738373464).

The spelling of 1531314242113 in words is "one trillion, five hundred thirty-one billion, three hundred fourteen million, two hundred forty-two thousand, one hundred thirteen".

Divisors: 1 19 209567 384581 3981773 7307039 80595486427 1531314242113