Base | Representation |
---|---|
bin | 1101111011010110111110… |
… | …1111011011010111110111 |
3 | 2000012221122111001022022020 |
4 | 3132311233233123113313 |
5 | 4001343402334122403 |
6 | 52322521041004223 |
7 | 3140234101540065 |
oct | 336655757332767 |
9 | 60187574038266 |
10 | 15313433114103 |
11 | 4974432855273 |
12 | 1873a19923673 |
13 | 871087086bc7 |
14 | 3ad261ac7035 |
15 | 1b850e2ca453 |
hex | ded6fbdb5f7 |
15313433114103 has 8 divisors (see below), whose sum is σ = 20417946729216. Its totient is φ = 10208937454200.
The previous prime is 15313433114101. The next prime is 15313433114123. The reversal of 15313433114103 is 30141133431351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 15313433114103 - 21 = 15313433114101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15313433114101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2353693 + ... + 6013878.
It is an arithmetic number, because the mean of its divisors is an integer number (2552243341152).
Almost surely, 215313433114103 is an apocalyptic number.
15313433114103 is a deficient number, since it is larger than the sum of its proper divisors (5104513615113).
15313433114103 is an equidigital number, since it uses as much as digits as its factorization.
15313433114103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8977605.
The product of its (nonzero) digits is 19440, while the sum is 33.
Adding to 15313433114103 its reverse (30141133431351), we get a palindrome (45454566545454).
The spelling of 15313433114103 in words is "fifteen trillion, three hundred thirteen billion, four hundred thirty-three million, one hundred fourteen thousand, one hundred three".
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