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153142441 = 236658367
BaseRepresentation
bin10010010000011…
…00010010101001
3101200011102221021
421020030102221
5303201024231
623110212441
73536455264
oct1110142251
9350142837
10153142441
1179499201
1243354121
132595c33a
14164a5cdb
15d6a0811
hex920c4a9

153142441 has 4 divisors (see below), whose sum is σ = 159800832. Its totient is φ = 146484052.

The previous prime is 153142439. The next prime is 153142447. The reversal of 153142441 is 144241351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 144241351 = 349413299.

It is a cyclic number.

It is not a de Polignac number, because 153142441 - 21 = 153142439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (153142447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3329161 + ... + 3329206.

It is an arithmetic number, because the mean of its divisors is an integer number (39950208).

Almost surely, 2153142441 is an apocalyptic number.

It is an amenable number.

153142441 is a deficient number, since it is larger than the sum of its proper divisors (6658391).

153142441 is an equidigital number, since it uses as much as digits as its factorization.

153142441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6658390.

The product of its digits is 1920, while the sum is 25.

The square root of 153142441 is about 12375.0733735199. The cubic root of 153142441 is about 535.0140515132.

Adding to 153142441 its reverse (144241351), we get a palindrome (297383792).

The spelling of 153142441 in words is "one hundred fifty-three million, one hundred forty-two thousand, four hundred forty-one".

Divisors: 1 23 6658367 153142441