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153150021143 = 71011049206501
BaseRepresentation
bin1000111010100001110…
…0111101111000010111
3112122022021210011112022
42032220130331320113
510002122401134033
6154204532243355
714031125462240
oct2165034757027
9478267704468
10153150021143
1159a50215709
122582177055b
131159906c3b2
1475abc89cc7
153eb5409098
hex23a873de17

153150021143 has 16 divisors (see below), whose sum is σ = 176930913600. Its totient is φ = 129847200000.

The previous prime is 153150021097. The next prime is 153150021149. The reversal of 153150021143 is 341120051351.

It is not a de Polignac number, because 153150021143 - 214 = 153150004759 is a prime.

It is a super-3 number, since 3×1531500211433 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (153150021149) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 638393 + ... + 844893.

It is an arithmetic number, because the mean of its divisors is an integer number (11058182100).

Almost surely, 2153150021143 is an apocalyptic number.

153150021143 is a deficient number, since it is larger than the sum of its proper divisors (23780892457).

153150021143 is a wasteful number, since it uses less digits than its factorization.

153150021143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 207658.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 153150021143 its reverse (341120051351), we get a palindrome (494270072494).

The spelling of 153150021143 in words is "one hundred fifty-three billion, one hundred fifty million, twenty-one thousand, one hundred forty-three".

Divisors: 1 7 101 707 1049 7343 105949 206501 741643 1445507 20856601 145996207 216619549 1516336843 21878574449 153150021143