Base | Representation |
---|---|
bin | 100010110101110111011100… |
… | …010010011111011001110101 |
3 | 202002120010221121221012122100 |
4 | 202311313130102133121311 |
5 | 130041101234434213013 |
6 | 1301523144352052313 |
7 | 44163611124400053 |
oct | 4265673422373165 |
9 | 662503847835570 |
10 | 153235244054133 |
11 | 4490977a4856aa |
12 | 1522a025234099 |
13 | 676703834bb87 |
14 | 29ba8a80ad1d3 |
15 | 12ab0012d5473 |
hex | 8b5ddc49f675 |
153235244054133 has 12 divisors (see below), whose sum is σ = 228479790418048. Its totient is φ = 98861447776680.
The previous prime is 153235244054041. The next prime is 153235244054159. The reversal of 153235244054133 is 331450442532351.
153235244054133 is a `hidden beast` number, since 1 + 5 + 3 + 2 + 3 + 524 + 40 + 54 + 1 + 33 = 666.
It is not a de Polignac number, because 153235244054133 - 28 = 153235244053877 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153235244054933) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 274615132435 + ... + 274615132992.
Almost surely, 2153235244054133 is an apocalyptic number.
It is an amenable number.
153235244054133 is a deficient number, since it is larger than the sum of its proper divisors (75244546363915).
153235244054133 is a wasteful number, since it uses less digits than its factorization.
153235244054133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 549230265464 (or 549230265461 counting only the distinct ones).
The product of its (nonzero) digits is 2592000, while the sum is 45.
Adding to 153235244054133 its reverse (331450442532351), we get a palindrome (484685686586484).
The spelling of 153235244054133 in words is "one hundred fifty-three trillion, two hundred thirty-five billion, two hundred forty-four million, fifty-four thousand, one hundred thirty-three".
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